Sumários
Separation Bc =/= Ex*
15 novembro 2013, 14:30 • José Félix Costa
Sistems of recursive simultaneous equations involving function indexes. (a)
Cases's operator recursion theorem \phi_{h(i)}(y) = \Phi(h)(<i,y>). (b)
Separation Bc =/= Ex* (proof based on (a) and (b)).
That R \notin Ex*.
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Problem set VI
Fix points of recursive operators
11 novembro 2013, 10:30 • José Félix Costa
Myhil-Shepherdson's theorems for recursive functionals.
Variants of Kleene's first recursion theorem (used to prove separations such like Ex* =/= Bc and Bc^{n} =/= Bc^{n+1}, for every n \in N).
Bc-identification
8 novembro 2013, 14:30 • José Félix Costa
That ASD* is in Ex* - \cup Ex^n.
Bc-identification (Barzdins, Case and Smith).
That Bc includes Ex* (Steel, Case and Smith). (Comment on the application of the argument of the proof in case studies in the History of Science.)
Discussion on the separation Bc =/= Ex*: the set S of recursive functions f such that, for all but finitely many values n, f(n) is a possible different index of f.
Ex^n hierarchy
4 novembro 2013, 10:30 • José Félix Costa
The n-variants and *-variants of recursive functions.
Ex^n- and Ex*-identification. The sets ASD^n and ASD* of almost self-describing functions with anomalies.
Case and Smith's theorem: ASD^(n+1) \in [ Ex^(n+1) - Ex^n ].
The non-collapsing hierarchy Ex \subset Ex^1 \subset Ex^2 \subset ... \subset Ex^n \subset Ex*.
That tolerating anomalies increases the inferring power of scientists. That research programs can induce omission errors: the case of Copernicus.
Parameterised scientists II
1 novembro 2013, 14:30 • José Félix Costa
Jantke theorem: That the set {i \in N : [i]f is TxtEx-identifiable}is not performable on [.]f .
That the set of indexes i such that #[i]f is finite is performable on [.]f.
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We also proved that there exists a collection of sets identifiable by a memory-limited scientist that is not TxtEx-identifiable by a memory-limited scientist.
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Problem set V.
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Solution to the identification of problem set III
LL is the class to be identified. Let W_a \not\in LL and f: N x N x N > N be one to one. D collects evidence, D_L is given by Angluin's theorem and m counts mind changes.
If W_i = L \in LL and D_L \subseteq D \cup {n} \subseteq L, then [ M(\sigma ^ n) = if m < n then f(i,D,m) else f(i,D \cup {n},m) ].
If (W_i \not\in LL or D \cup {n} \not\subseteq W_i) and (there exists L \not\in LL such that D_L \subseteq D \cup {n} \subseteq L, then [ M(\sigma ^ n) = f(j,D \cup {n},m+1) ], where j is the least index of L.
Otherwise M(\sigma ^ n) = f(a,D \cup {n},m+1).